Lösung zu Pumpspeicherwerk

1. [math]\eta_{Turbine} = \frac {P_{elektr}}{P_{hydr}} = \frac {P_{elektr}}{\rho g \Delta h I_V}[/math]= 0.943 (94.3%)
2. [math]\eta_{Pumpe} = \frac {P_{hydr}}{P_{elektr}}[/math] [math]P_{elektr} = \frac{P_{hydr}}{\eta} = \frac{\rho g \Delta h I_V}{\eta}[/math] = 333 MW
3. 1-η² = 0.111 oder 11.1% Verlust

Aufgabe